2016临汾市高考考前适应性训练二 高考作文

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第一篇:《临汾市2016高考考前理科数学适应性训练二》

临汾市2016高考考前理科数学适应性训练二

第二篇:《2016临汾市文科数学答案第二次考前适应性训练》

2016年第二次高考考前适应性训练试卷

文科数学试题参考答案和评分参考

一.选择题:

第II卷

二.填空题:

13、3

5 14、2 15、1

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12 16、[82,82]

三. 解答题:

17、解:

(1)因为CD2,CD2BD,所以BD1,BC3BD3,

则在直角三角形ABC中,cosCAC2

BC3,.......................................3分

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在三角形ACD中,由余弦定理可得

AD2AC2CD22ACCDcosC8

3, 所以AD26

3.......................................................................................6分

(2)因为ADBD,所以DABB,

ADC2B,又因为ACCD,所以CAD2B,.............9分

所以CAB3B90,

所以角B的大小为30............................................................................12分

18、解:

(1)证明:连接BD交AC于点F,连接EF.

因为四边形ABCD是菱形,所以F是线段BD的中点.

因为E是线段PB的中点,所以EF//PD...........................................2分

因为PD面ACE,EF面ACE,所以PD//面ACE..............4分

(2)设AD中点为O,连接BO交AC于点M,并延长BO到点N,

使得ONOM,连接PN,EM.

因为菱形ABCD中ABC120,所以ABD为等边三角形,

因为BO,AF分别是AD,BD边上的中线,所以M是ABD的重心,

所以AM2

3AF1

3AC,........................................................................6分

所以点M是点E在面ABCD上的射影,所以EM面ABCD. 因为ONOM1

3OB,所以MNMB,即M是线段BN的中点.

因为E是线段PB的中点,所以PN//EM,PN2EM,

A

443BO.所以PN面ABCD.......................................8分 33

12,...........................................10分 VBACEVEABCSABCEM33

所以EM2,PN4,.........................................................................11分成公英 822所以PBPNBN.........................................................12分 3BN

19、解:

(1)由茎叶图知:食品蛋白质含量在[5,7)内的频数为2,在[11,13)内的频数为3,所以,

21,b3...............................................2分 2010

由上表知,食品蛋白质含量在[7,9)内的频数为:200.255,

则食品蛋白质含量在[7,8)内的频数为:532,

所以,食品蛋白质含量在[9,10)内的频数为:201244.........4分 a

(2)由茎叶图知,食品蛋白质含量大于11的数据有5个,

分别为:11.3,11.6,12.0,13.1,14.2,

将这5袋分别记为:A,B,C,D,E,

则在这5袋中任取2袋的基本事件有:(A,B),(A,C),(A,D),

(A,E),(B,C),(B,D),(B,E),(C,D),(C,E),(D,E),

共10种,.....................................................................................................6分

其中,两袋都落在同一组内的基本事件有:

(A,B),(A,C),(B,C),(D,E),共4种,............................7分

所以,2袋都落在同一组内的概率为:p42...........................8分 105

(3)由题知,蛋白质含量不高于8克的食品的概率估计值为:

p160.3,........................................................................................10分 20

则蛋白质含量高于8克的食品的概率估计值为:

p21p110.30.7,..................................................................11分

由于0.780%,因此,不能认为该批食品符合“蛋白质含量高于8克的食品至少要占全部食品的80%”的规定...................................................12分

20、解:

p2,所以p4, 2

2可得抛物线C2的方程为x8y,........................................................2分 (1)由题可知:

2将点(2,2)代入圆C1方程中得r6,

所以圆C1的方程为xy6.............................................................5分

(2)设点P(2,2),A(x1,y1),B(x2,y2), 22

121x,所以yx, 84

1所以直线AP的方程为:yy1x1(xx1), 4

2x12,...........................................7分 将(2,2)代入上式得:y14抛物线的方程可化为:y

同理可得直线BP的方程为:y2

所以直线AB的方程为:y2x22,...................................8分 42x2...............................................10分 4

842(0,0)圆心到直线AB的距离d,...........................11分 3216

42222...........................................................12分 EF2633

21、解: 2

1(x0),.......................................................1分 x

因为函数f(x)在x1处取极值,所以f(1)2ab10,

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所以b12a,.........................................................................................2分 11则f(x)2ax12a(x1)(2a)(x0). xx

1当a0时,2a0,则x(0,1)时,f(x)0; x

x(1,)时,f(x)0........................................................................3分

所以函数f(x)的单调递增区间为(1,),单调递减区间为(0,1]......4分 (1)f(x)2axb2016临汾市高考考前适应性训练二

(2)由(1)知f(x)ax2(12a)xclnx,

因为函数f(x)在x1处取极值1c,

所以f(1)a1c1c,可得a2,......................................5分

因为a0,由(1)可知函数f(x)区间(1,)上单调递增,

在区间(0,1]上单调递减,

所以f(x)minf(1)1c,................................................................6分

因为不等式f(x)2c恒成立,

所以有1c2c,解得c1或c

所以实数c的取值范围是c1或c221, 21.............................................7分(3)由(1)知2

b12a,2016临汾市高考考前适应性训练二

所以lna(2b)lna4a2,............................................................9分

构造函数g(a)lna4a2,..............................................................10分 1则g

(a)4,所以有 所以g(a)maxg()ln1ln0,..........................................11分 444

所以g(a)0恒成立,即lna2b...................................................12分2016临汾市高考考前适应性训练二

22、解:

(1)证:连接BN,交OP于点Q.

PB、PN分别与⊙O相切于点B、N,

OBP≌ONP,.......................2分

BQQN,

NQP90,

QPN90QNP,.........4分

又AB为⊙O的直径,

ANB90,

ANM90QNP,

QPNANM,

AN//OP............................................................................................6分

1(2)AB4,OBAB2, 2

又BP6,OBP90,

OB23,.....................................................8分 tanOPBBP632016临汾市高考考前适应性训练二

OPB30,OPNOPB30,

NPB60,M30,OMOP,

又ONMP,MNNP......................................................10分

23、解:

(1)直线l的普通方程为:y2x4,

由于xcos,ysin,

则直线l的极坐标方程为:sin2cos40.......................4分

(2)设Mx,2x4,

MA切圆C于点A,且圆C的圆心C0

MA

MA2MC22分 1,2又MC2x22x41M5x2N5, 25x244,当且仅当x2时,取“”. MA的最小值为2,且此时点M的直角坐标为2,0,...........9分 则点M的极坐标为2,..................................................................10分

24、解:

(1)依题知 关于x的不等式xmn的解集为

xmnxmn,........................................................................2分 又由于关于x的不等式xmn的解集为x0x4, mn0, mn4,

解得:mn2..................................................................................5分

mn(2)ab,mn2, ab

22ab, ab

又a0,b0,

2b2a2b2a22242abab48, ababab

,......................9分 ab22,当且仅当ab2时,取“”

ab的最小值为22....................................................................10分

第三篇:《临汾市2014年高考考前适应性训练考试(二)》

临汾市2014年高考考前适应性训练考试(二)

7. How did Rose think about herself?

A. Careless B. Careful C. Pretty 听第7段材料,回答第8至10题。 8. What is Venice?

A. A street B. A canal C. A city 9. How do people ride about the city in Venice?

A. In boats B. In cars C. In buses 10. Where is Venice?

A. In Canada B. In England C. In Italy 听第8段材料,回答第11至13题。 11. Why does Julia want to leave her present job?

A. Because she does not like the job B. Because she wants to do something different C. Because she wants to travel and teach English 12. What is Tom’s attitude toward Julia’s leaving her job?

A. He doesn’t think it is a good idea B. He feels it stupid of her to do so C. He understands Julia’s decision 13. Who do you think Tom is most likely to be?

A. Julia’s boss B. Julia’s boyfriend C. Julia’s husband 听第9段材料,回答第14至16题。

14. Where do you think the speaker made this speech?

A. At the opening of a hotel B. At a trade fair(交易会) C. At the opening of a meeting 15. Whom was the speaker speaking to?

A. People of all ages and from different countries B. Young people from different parts of the world Businessmen from other cities in his own country 16. What was the main topic of the speech?

A. Friendship among all the people in the world B. World Trade C. World Peace 听第10段材料,回答第17至20题。 17. What do the pupils do after breakfast?

A. They work out their plan for the day B. They talk to the teachers C. They make lunch themselves

18. When the pupils in the free school go somewhere else, what do they want to learn? A. How to draw B. How to drive C. Math 19. What do most pupils enjoy doing in the school?

A. Drawing B. Washing-up C. Cooking 20. On which day is the school open for the longest hours?

A. Saturday B. Tuesday C. Thursday 第二部分 阅读理解(共两节,满分60分) 第一节 (共15小题;每小题3分,满分45分)

阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该选

英 语

本试卷分第I卷(选择题)和第II卷(非选择题)。满分150分;考试时间120分钟。考试结束,将本试卷和答题卡一并交回。(听力部分满分30分,不计入总分,考试成绩录取时提供高校做参考。)

第I卷

注意事项:

1. 答第I卷题前,考生务必将自己的姓名、准考证号填写在答题卡上。

2. 选出每小题的答案后,用铅笔把答题卡上对应题目的答案标号涂黑。如需改动,用橡皮擦干净后,

再涂其它答案标号。不能答在本试卷上,否则无效。

3. 听力部分满分30分,不计入总分,考试成绩录取时提供高校做参考。 第一部分 听力(共两节,满分30分,不计入总分)

做题时,先将答案标在试卷上。录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节 (共5小题;每小题1.5分,满分7.5分)

听下面5段对话。每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。

1. What does the woman imply?

A. It would be better to call another time B. Jack gets home late in the morning C. She has already called Jack 2. What was the score?

A. 0: 40 B. 0: 4 C. 0: 14 3. How many dresses does the woman have at least?

A. One B. Two C. Three 4. What does the woman mean?

A. She went to a picnic yesterday B. She doesn’t like picnic at all C. She is very busy today

5. How much does he have to pay if he buys one today?

A. $ 4 B. $ 4. 50 C. $ 3. 50 第二节 (共15小题;每小题1.5分,满分22.5分)

听消灭几段对话或独白。每段对话或独白后有几个小题。从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。每段对话或独白都两遍。 听第6段材料,回答第6至7题。 6. What did they do today?

A. They had a physical training B. They had a test in physics C. They had a test in math

项涂黑。

A

You must be familiar with the witty skit To help or not to help at the 2014 Spring Festival Gala, aren’t you? Should we reach out our hands or turn a blind eye when we see someone need help? I’m sure you have an answer in your heart. In most cases, we shall help ourselves by helping others, for whatever good we give out completes the circle and comes back to us. Here Greg O’ Leary shares his experience on one of American city streets.

I was walking down a dimly lit street late on evening when I heard screams coming from behind a clump of bushes. Alarmed, I slowed down to listen, and panicked when I realized that what I was hearing were the sounds of a struggle. Only yards from where I stood, a woman was being attacked.

Should I get involved? I was frightened for my own safety, and cursed myself for having suddenly decided to take a new route home that night. What if I became another statistic Shouldn’t I just run to the nearest hone and call the police?

’s cries were growing weaker. I knew I had to act fast. I asked myself “How could I walk away from this?” “No”, I finally resolved, “I could not turn my back on the fate of this unknown woman, even if it meant risking my own life.”

I am not a brave man, nor am I athletic. I don’t know where I found the moral, courage and physical strength, but once I had finally resolved to help the girl, I became strangely transformed. I ran behind the bushes and pulled the attacker off the woman. Struggling, we fell to the ground, where we wrestled for a few minutes until the attacker jumped up and escaped.

Breathing heavily, I got to my feet and approached the girl, who was sobbing behind a tree. In the

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